Podem me ajudar, por favor?
sec1320°/2 - 2cos(53π/3) + tg(2220°)²
(sec240°/2 - 2cos300° + tg(60)²)
O valor numérico da expressão acima é:
a.-1
b.0
c.1/2
d.1
e.√3/2
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