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NicolasPG
@NicolasPG
December 2019
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6x+2y=10
3y-x=5
como resolver pelo método de adição?(as duas são juntas)
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leonardoposs
6x+2y=10
(-x+3y =5)vezes 6
=
20y=40
y=40/20
y=2
6x+2 . 2=10
6x+4=10
6x=10-4
6x=6
x=6/6
x=1
S{1,2}
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Lista de comentários
(-x+3y =5)vezes 6
=
20y=40
y=40/20
y=2
6x+2 . 2=10
6x+4=10
6x=10-4
6x=6
x=6/6
x=1
S{1,2}