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Gemesson
@Gemesson
October 2019
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Achar as dimensoes de um paralelepipedo retângulo sabendo que são elas proporcionais aos numeros 2, 3 e 5 e que a árca toatl é 3038 cm².?
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MiraelsonBarbosa
Area Total = 2 ( a.b + a.c + b.c)
3038 = 2 ( a.b + a.c + b.c)
1519 = ( a.b + a.c + b.c) fazendo
a/2 = b/3 = c/5 = k
a = 2k, b = 3k , c = 5k
1519 = 2k.3k + 2k.5k + 3k.5k
1519 = 6k² + 10k² + 15k²
1519 = 31k²
k² = 1519/31
k² = 49, logo k = 7
a = 2k = 2.7 = 14 cm
b = 3k = 3.7 = 21 cm
c = 5k = 5.7 = 35 cm
3 votes
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Lista de comentários
3038 = 2 ( a.b + a.c + b.c)
1519 = ( a.b + a.c + b.c) fazendo
a/2 = b/3 = c/5 = k
a = 2k, b = 3k , c = 5k
1519 = 2k.3k + 2k.5k + 3k.5k
1519 = 6k² + 10k² + 15k²
1519 = 31k²
k² = 1519/31
k² = 49, logo k = 7
a = 2k = 2.7 = 14 cm
b = 3k = 3.7 = 21 cm
c = 5k = 5.7 = 35 cm