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Dyogoandrade67
@Dyogoandrade67
December 2019
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Ache os zeros da função: f(x)= x²-7x+10
Quero calculo por favor
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barbarabarros27
A=1 b=7 c=10
∆=b²-4.a.c
∆=7²-4.1.10
∆=49-40
∆=9
1 votes
Thanks 1
3478elc
f(x)= x²-7x+10
Δ = (-7)² - 4.1.10 = 49 - 40 = 9
x = 7+/-3
2
x1 = 5 ; x2 = 2
2 votes
Thanks 0
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Lista de comentários
∆=b²-4.a.c
∆=7²-4.1.10
∆=49-40
∆=9
f(x)= x²-7x+10
Δ = (-7)² - 4.1.10 = 49 - 40 = 9
x = 7+/-3
2
x1 = 5 ; x2 = 2