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Dyogoandrade67
@Dyogoandrade67
December 2019
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Determine o vértice da função quadrática f(x)= -10x²-20x-40
Qual é o valor de Delta???
Calculo
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Lonk
O valor de Delta é:
Delta=
-4(a).(c)
substituindo fica:
20²-4(-10)(-40)
400-1600
Delta=-1200
3 votes
Thanks 1
Lonk
vertice do X= -b/2a
Lonk
substituindo fica -(-20)/2(-10)
Lonk
que é igual a 20/-20=-1 (X vértice)
Lonk
vertice do Y= -(delta)/4a
Lonk
-(-1200)/4(-10)=-30 (Y vértice)
Lonk
espero ter ajudado :)
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Delta= -4(a).(c)
substituindo fica:
20²-4(-10)(-40)
400-1600
Delta=-1200