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Guilhermecgpra
@Guilhermecgpra
January 2020
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Alguem me socorre, preciso disso pra segunda
Meu professor passou essa formula: a²=b²+c²
Calcule o valor de x:
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JuarezJr
A) x² = (√3)² + (√2)²
x² = 3 + 2
x² = 5
x = √5
b) (2x)² = (3√3)² + x²
4x² = 9·3 + x²
4x² - x² = 27
3x² = 27
x² =
27
3
x² = 9
x = √9
x = 3
c) 6² = (3√5)² + x²
36 = 9·5 + x²
36 = 45 + x²
x² = 45 - 36
x² = 9
x = √9
x = 3
d) (x + 5)² = 6² + (x + 3)²
x² + 2·x·5 + 5² = 36 + x² + 2·x·3 + 3²
x² + 10x + 25 = 36 + x² + 6x + 9
x² - x² + 10x - 6x = 36 + 9 - 25
4x = 20
x =
20
4
x = 5
1 votes
Thanks 1
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Lista de comentários
x² = 3 + 2
x² = 5
x = √5
b) (2x)² = (3√3)² + x²
4x² = 9·3 + x²
4x² - x² = 27
3x² = 27
x² = 27
3
x² = 9
x = √9
x = 3
c) 6² = (3√5)² + x²
36 = 9·5 + x²
36 = 45 + x²
x² = 45 - 36
x² = 9
x = √9
x = 3
d) (x + 5)² = 6² + (x + 3)²
x² + 2·x·5 + 5² = 36 + x² + 2·x·3 + 3²
x² + 10x + 25 = 36 + x² + 6x + 9
x² - x² + 10x - 6x = 36 + 9 - 25
4x = 20
x = 20
4
x = 5