Calcule a área dos triângulos de vértices:
A) A(0,0), B(4,0) e C( 4,2)
B) A(-3,2), B(2,3) e C(5,-2)
A) A(0,0), B(4,0) e C( 4,2)
B) A(-3,2), B(2,3) e C(5,-2)
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A) 0 0 1 0 0
4 0 1 4 0 = D/2 = A = 8/2 = 4
4 2 1 4 2
B) -3 2 1 -3 2
2 3 1 2 3 = D/2 = A = -9 + 10 + 4 -15 -6 -4 = 20/2 = 10
5 -2 1 5 -2