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Mannucat
@Mannucat
December 2019
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Calcule o 1° termo da PG a3=x, a5=162 e a6=27x.
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crazynds
A3=X
a5=162
a6=27x
r=a6/a5
r=27x/162=x/6
r=x/6
a5/a3=r^2
162/x=r^2
162/x=(x/6)^2
162/x=x^2/36
**regra de 3**
x^3=5833
x=18
r=18/6=3
a1=a3/(r^2)
a1=18/9
a1=2
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Thanks 1
crazynds
sou mt bom u.u
Mannucat
Vlw
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a5=162
a6=27x
r=a6/a5
r=27x/162=x/6
r=x/6
a5/a3=r^2
162/x=r^2
162/x=(x/6)^2
162/x=x^2/36
**regra de 3**
x^3=5833
x=18
r=18/6=3
a1=a3/(r^2)
a1=18/9
a1=2