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Izabellly
@Izabellly
May 2020
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Simplifique
2-sen²x-tg²x/cos²x
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lahfortunato
[(2 - sen ² x)/cos ² x] - (sen ² x/ cos ² x) = ( 2 - sen ² x - sen ² x)/cos ² x
= (2 - 2 sen ² x)cos ² x = 2(1 - sen ² x)/cos ² x = 2(cos ² x)/cos ² x = 2
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izabellly
tenho outra questão parecida vc poderia me ajudar?
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= (2 - 2 sen ² x)cos ² x = 2(1 - sen ² x)/cos ² x = 2(cos ² x)/cos ² x = 2