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@Marcionedes
December 2019
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Dados log2 = 0,3010 e log5 = 0,6990, calcule:
a)
b)
c)
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TiagoEd
A) Log 125
= Log 5³
= 3 Log5
= 3 * 0,6990
= 2,097
b) Log 5/2
= Log5 - Log 2
= 0,6990 - 0,3010
= 0,398
c) Log 10
10^x = 10
10^x = 10^1
x = 1
3 votes
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Lista de comentários
= Log 5³
= 3 Log5
= 3 * 0,6990
= 2,097
b) Log 5/2
= Log5 - Log 2
= 0,6990 - 0,3010
= 0,398
c) Log 10
10^x = 10
10^x = 10^1
x = 1