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ThiziaAllenSyl15
@ThiziaAllenSyl15
January 2020
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Determine o vértice V da parábola que representa a função quadrática.
A) y= (x-2)^2 +3
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tia3255
(x - 2)² + 3 = 0
x² - 4x + 4 + 3 = 0
x² - 4x + 7 = 0
a = 1 b = - 4 c = 7
Δ = b² - 4.a.c
Δ = ( - 4 )² - 4.1.7
Δ = 16 - 28
Δ = - 12
- b - Δ
Vx = ------- Vy = ------
2.a 4.a
- ( - 4) - ( - 12 )
Vx = ------------ Vy = -------------
2.1 4.1
4 12
Vx = --------- Vy = --------
2 4
Vx = 2 Vy = 3 V{(2 , 3)}
4 votes
Thanks 3
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Lista de comentários
x² - 4x + 4 + 3 = 0
x² - 4x + 7 = 0
a = 1 b = - 4 c = 7
Δ = b² - 4.a.c
Δ = ( - 4 )² - 4.1.7
Δ = 16 - 28
Δ = - 12
- b - Δ
Vx = ------- Vy = ------
2.a 4.a
- ( - 4) - ( - 12 )
Vx = ------------ Vy = -------------
2.1 4.1
4 12
Vx = --------- Vy = --------
2 4
Vx = 2 Vy = 3 V{(2 , 3)}