Bonjour,

Réponse :

[tex]\textbf{ a) } 125 \:\underbrace{0..........0}_{\sf 12\:z\acute{e}ros} = 125\times 10^{12} = \boxed{1,25\times 10^{14} }[/tex]

[tex]\textbf{ b) } 0,\underbrace{0..........0}_{\sf 10\:z\acute{e}ros}29 = 0,29\times 10^{-10} = \boxed{2,9\times 10^{-11} }[/tex]

[tex]\textbf{ c) } 25\underbrace{0..........0}_{\sf 10\:z\acute{e}ros} = 25\times 10^{10} = \boxed{2,5\times 10^{11} }[/tex]

[tex]\textbf{ d) } 125 \:\underbrace{0..........0}_{\sf 12\:z\acute{e}ros} = 125\times 10^{12} = \boxed{1,25\times 10^{14} }[/tex]

[tex]\textbf{ e) } 0,\underbrace{0..........0}_{\sf 15\:z\acute{e}ros}278 = 0,278\times 10^{-15} = \boxed{2,78\times 10^{-16} }[/tex]

[tex]\textbf{ f) } 37\underbrace{0..........0}_{\sf 12\:z\acute{e}ros} = 37\times 10^{12} = \boxed{3,7\times 10^{13} }[/tex]

[tex]\textbf{ g) } 0,\underbrace{0..........0}_{\sf 20\:z\acute{e}ros}\:356 = 0,356\times 10^{-20} = \boxed{3,56\times 10^{-21} }[/tex]

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En espérant t'avoir aidé, bonne continuation ! ☺️