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Thainejw
@Thainejw
May 2020
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Resolva as equaçôes a seguir:
a)18x-43=65
b)23x-16 =14-17x
c)10y-5(1+y)=3 (2y-2)-20
d)x(x+4)+x(x+2)=2x^2 + 12
me ajudem pf!! tem que encontrar o valor de x.
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clarttm
Verified answer
Na questão a: 18x-43=65
18x=43+65
18x=108
x=108/18
x=6
1 votes
Thanks 1
eluciamonteiro
a)18x-43=65
18x = 65 + 43
18x = 108
x = 108/18
x = 6
S[6]
b)23x-16 =14-17x
23x + 17x = 14 + 16
40x = 30
x =
30
÷ 10
40 ÷ 10
x =
3
4
S[3/4]
c)10y-5(1+y)=3 (2y-2)-20
10y - 5 - 5y = 6y - 6 - 20
10y - 5y - 6y = - 6 - 20 + 5
10y - 11y = - 26 + 5
- y = - 21.(-1)
y = 21
S[21]
d)x(x+4)+x(x+2)=2x^2 + 12
x² + 4x + x² + 2x = 2x² + 12
x² + x² - 2x² + 4x + 2x - 12 = 0
+ 2x² - 2x² + 6x - 12 = 0 cancela 2x² - 2x²
6x - 12 = 0
6x = 12
x = 12/6
x = 2
S[2]
0 votes
Thanks 2
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Verified answer
Na questão a: 18x-43=6518x=43+65
18x=108
x=108/18
x=6
18x = 65 + 43
18x = 108
x = 108/18
x = 6
S[6]
b)23x-16 =14-17x
23x + 17x = 14 + 16
40x = 30
x = 30 ÷ 10
40 ÷ 10
x = 3
4
S[3/4]
c)10y-5(1+y)=3 (2y-2)-20
10y - 5 - 5y = 6y - 6 - 20
10y - 5y - 6y = - 6 - 20 + 5
10y - 11y = - 26 + 5
- y = - 21.(-1)
y = 21
S[21]
d)x(x+4)+x(x+2)=2x^2 + 12
x² + 4x + x² + 2x = 2x² + 12
x² + x² - 2x² + 4x + 2x - 12 = 0
+ 2x² - 2x² + 6x - 12 = 0 cancela 2x² - 2x²
6x - 12 = 0
6x = 12
x = 12/6
x = 2
S[2]