Articles
Register
Sign In
Search
Jhonyudsonbr
@Jhonyudsonbr
January 2020
1
37
Report
Sabendo que 3x-1 é fator de : 12x³-19x²+8x-1 então as soluções reais das equação:
12.(3^3x)-19.(3^2x)+8.(3^x)-1=0 somam:
resolução por favor !!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
albertrieben
Boa tarde Jhonyduson
12*3^3x - 19*3^2x + 8*3^x - 1 = 0
y = 3^x
12y^3 - 19y^2 + 8y - 1 = 0
3^x - 1 = y - 1
(12y^3 - 19y^2 + 8y - 1)/(y - 1) = 12y^2 - 7y + 1
12y^2 - 7y + 1 = 0
delta
d^2 = 49 - 48 = 1
d = 1
y2 = (7 + 1)/24 = 8/24 = 1/3
y3 = (7 - 1)/24 = 6/24 = 1/4
y1 = 1
3^x1 = 1 = 3^0 , x1 = 0
3^x2 = 1/3 = 3^-1 , x2 = -1
3^x3 = 1/4 , x3 = -2log(2)/(log(3)) = -1.2619
soma
S = 0 - 1 - 1.2619 = -2.2619
2 votes
Thanks 1
jhonyudsonbr
bem detalhado, obrigado mesmo !!
More Questions From This User
See All
jhonyudsonbr
October 2023 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Jhonyudsonbr
January 2020 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Sabendo que 3x-1 é fator de : 12x³-19x²+8x-1 então as soluções reais das equação:12.(3^3x)-19.(3^2x).... Pergunta de ideia de Jhonyudsonbr"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
12*3^3x - 19*3^2x + 8*3^x - 1 = 0
y = 3^x
12y^3 - 19y^2 + 8y - 1 = 0
3^x - 1 = y - 1
(12y^3 - 19y^2 + 8y - 1)/(y - 1) = 12y^2 - 7y + 1
12y^2 - 7y + 1 = 0
delta
d^2 = 49 - 48 = 1
d = 1
y2 = (7 + 1)/24 = 8/24 = 1/3
y3 = (7 - 1)/24 = 6/24 = 1/4
y1 = 1
3^x1 = 1 = 3^0 , x1 = 0
3^x2 = 1/3 = 3^-1 , x2 = -1
3^x3 = 1/4 , x3 = -2log(2)/(log(3)) = -1.2619
soma
S = 0 - 1 - 1.2619 = -2.2619