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EullerGomes
@EullerGomes
June 2019
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Se a + b = 5 e a.b =-8, o valor de a² + 4a.b + b² é:
a) 9
b) 25
c) -7
d) 41
e) 57
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rbgrijo2011
(a+b) = 5
(a+b)² = 5²
a²+b² + 2.(a.b) = 25
a²+b² + 2.(-8) = 25
a²+b² - 16 = 25
a²+b² = 25 +16
a²+b² = 41
a²+b² +4(ab)
41 + 4(-8)
41 - 32
9 ✓
1 votes
Thanks 2
EullerGomes
muito obrigado, você me ajudou muito.
Raiher
Se elevarmos a primeira equação ao quadrado e adicionarmos 2ab a ambos os membros, temos:
RESPOSTA:Letra A
1 votes
Thanks 3
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Lista de comentários
(a+b)² = 5²
a²+b² + 2.(a.b) = 25
a²+b² + 2.(-8) = 25
a²+b² - 16 = 25
a²+b² = 25 +16
a²+b² = 41
a²+b² +4(ab)
41 + 4(-8)
41 - 32
9 ✓
RESPOSTA:Letra A