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Necilyan
@Necilyan
April 2020
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Se f(x)=1 e f(x)=x²-5x+7. Qual o valor de x?
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Guther
f(x)=1 e f(x)=x²-5x+7
x² - 5x + 7 = 1
x² - 5x + 7 - 1 = 0
x² - 5x + 6 = 0
a = 1 b = - 5 c = 6
∆ = b² - 4 . a . c
∆ = (- 5)² - 4 . 1 . 6
∆ = 25 - 24
∆ = 1
x =
- b
+
√∆
----------------
2
a
x = - (- 5)
+
√1
------------------
2 . 1
x = 5
+
1
-----------
2
x' =
5 + 1
2
x' = 6 : 2
x' = 3
x" =
5 - 1
2
x" = 4 : 2
x" = 2
Raízes: {3, 2}
1 votes
Thanks 2
fabriciords38
f(x)=1 e f(x)=x²-5x+7
x
²-5x+7=1
x²-5x+7-1
x²-5x+6=0
Δ=b²-4.a.c
Δ=5²-4.1.6
Δ=25-24
Δ=1
x=
-b
+
√Δ
2a
x=
-5
+
√
1
2.1
x=
5
+
1
x₁=
5+1
=
6
= 3
2 2
2
x₂=
5-1
=
4
= 2
2 2
x₁= 3
x₂=2
espero ter ajudado
1 votes
Thanks 2
fabriciords38
espero ter ajudado
Necilyan
Ajudou sim! Obg :)
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Lista de comentários
x² - 5x + 7 = 1
x² - 5x + 7 - 1 = 0
x² - 5x + 6 = 0
a = 1 b = - 5 c = 6
∆ = b² - 4 . a . c
∆ = (- 5)² - 4 . 1 . 6
∆ = 25 - 24
∆ = 1
x = - b + √∆
----------------
2a
x = - (- 5) + √1
------------------
2 . 1
x = 5 + 1
-----------
2
x' = 5 + 1
2
x' = 6 : 2
x' = 3
x" = 5 - 1
2
x" = 4 : 2
x" = 2
Raízes: {3, 2}
x²-5x+7=1
x²-5x+7-1
x²-5x+6=0
Δ=b²-4.a.c
Δ=5²-4.1.6
Δ=25-24
Δ=1
x= -b + √Δ
2a
x= -5 + √1
2.1
x= 5 + 1 x₁= 5+1 = 6 = 3
2 2 2
x₂= 5-1 = 4 = 2
2 2
x₁= 3
x₂=2
espero ter ajudado