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Jessy0150
@Jessy0150
December 2019
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Seja f uma função real do 1 grau tal f (7)- f (3)=6. O valor de f(12)-f (9) e?
mim ajudrm pf
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gustavobarbon01
Equacao geral de função de primeiro grau:
f(x) = ax + b
f(7) - f(3) = 6
(7a + b) - (3a + b) = 6
7a + b -3a -b = 6
4a = 6
a = 6/4 = 3/2
f(12) - f(9) = t
(12.3/2 + b) - (9.3/2 + b) = t
18 +b -27/2 -b = t
t = 36/2 -27/2 = 9/2
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f(x) = ax + b
f(7) - f(3) = 6
(7a + b) - (3a + b) = 6
7a + b -3a -b = 6
4a = 6
a = 6/4 = 3/2
f(12) - f(9) = t
(12.3/2 + b) - (9.3/2 + b) = t
18 +b -27/2 -b = t
t = 36/2 -27/2 = 9/2