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Danwinster10
@Danwinster10
January 2020
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Sejam os polinômios P(X)= 3x ao cubo - 4x ao quadrado + x - 5, calcule os valores numéricos para:
A X=1
B X=0
C X=-3
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maell18
P(x) = 3x³ - 4x² + x - 5
A)
p(1) = 3.(1³) - 4.(1²) + 1 - 5
p(1) = 3.1 - 4.1 + 1 - 5
p(1) = 3 - 4 + 1 - 5
p(1) = - 5
B)
p(0) = 3.0³ - 4.0² + 0 - 5
p(0) = 3.0 - 4.0 + 0 - 5
p(0) = 0 - 0 + 0 - 5
p(0) = - 5
C)
p(- 3) = 3.(- 3)³ - 4.(- 3)² + (- 3) - 5
p(- 3) = 3.(- 27) - 4.9 - 3 - 5
p(- 3) = - 81 - 36 - 3 - 5
p(- 3) = - 125
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A)
p(1) = 3.(1³) - 4.(1²) + 1 - 5
p(1) = 3.1 - 4.1 + 1 - 5
p(1) = 3 - 4 + 1 - 5
p(1) = - 5
B)
p(0) = 3.0³ - 4.0² + 0 - 5
p(0) = 3.0 - 4.0 + 0 - 5
p(0) = 0 - 0 + 0 - 5
p(0) = - 5
C)
p(- 3) = 3.(- 3)³ - 4.(- 3)² + (- 3) - 5
p(- 3) = 3.(- 27) - 4.9 - 3 - 5
p(- 3) = - 81 - 36 - 3 - 5
p(- 3) = - 125