April 2020 1 104 Report
Sendo f(x) = sen²x + cos² x + cotg x + cessec x + tg x - sec , então f( \frac{ \pi }{3} vale :
a)  \frac{ \sqrt{3} }{2}
b) 3
c) 1/3
d)  \frac{ \sqrt{3}+3 }{2}
e) -1
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Sei que a resposta é -1. Mas como chegar até ela?
na trigonometria o pi equivale 180°;
sec² x + cos² x = 1 ;
cosec² x = sen² x;
sec = cos;
cosec = sen;
cotg = 1/tg;
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