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Marcos0661
@Marcos0661
June 2019
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Utilizando o teorema de Pitágoras determine as medidas indicadas:
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king77
E)x/2=2/2
2x=2×2
2x =4
x =4÷2
x =2
F)x/6=2/10
10x=6×2
10x =12
x=12÷10
x=1,2
G)15/23=10/x
15x =10×23
15x=230
x=230÷15
x=15,333333
0 votes
Thanks 1
Marcos0661
Muito obrigado
king77
Estou aqui para ajudar quem precisa
king77
E dn
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2x=2×2
2x =4
x =4÷2
x =2
F)x/6=2/10
10x=6×2
10x =12
x=12÷10
x=1,2
G)15/23=10/x
15x =10×23
15x=230
x=230÷15
x=15,333333