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NerdDiscolado
@NerdDiscolado
December 2019
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Verifique se a função é par ou impar:
\mathsf{f(x)=(x+1)^5+(x-1)^5}
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Shinichi
Vamos lá,
f(- x) = (- x + 1)^5 + (- x - 1)^5
f(- x) = [(- 1) * (x - 1)]^5 + [(- 1) * (x + 1)]^5
f(- x) = (- 1)^5 * (x - 1)^5 + (- 1)^5 * (x + 1)^5
f(- x) = (- 1) * (x - 1)^5 + (- 1) * (x + 1)^5
f(- x) = (- 1) * [(x - 1)^5 + (x + 1)^5]
f(- x) = - [(x + 1)^5 + (x - 1)^5]
f(- x) = - f(x)
Então f e impar.
Espero ajudar...
Duvidas?Comente!
2 votes
Thanks 1
NerdDiscolado
Obg ♥
Shinichi
Nd ♥
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Lista de comentários
f(- x) = (- x + 1)^5 + (- x - 1)^5
f(- x) = [(- 1) * (x - 1)]^5 + [(- 1) * (x + 1)]^5
f(- x) = (- 1)^5 * (x - 1)^5 + (- 1)^5 * (x + 1)^5
f(- x) = (- 1) * (x - 1)^5 + (- 1) * (x + 1)^5
f(- x) = (- 1) * [(x - 1)^5 + (x + 1)^5]
f(- x) = - [(x + 1)^5 + (x - 1)^5]
f(- x) = - f(x)
Então f e impar.
Espero ajudar...
Duvidas?Comente!