Sabendo que cosx=24/25 e 0.... Pergunta de ideia deJordana99freit

Jordana99freit @Jordana99freit

January 2020 1 24 Report

Sabendo que cosx=24/25 e 0<x<pi/2, calcule senx/4, cosx/4 e tgx/4

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albertrieben Boa tarde Jordana

cos(x) = 24/25

x = acos(24/25) = 16°26

sen(x/4) = sen(16.26/4) = 0.0708881
cos(x/4) = cos(16.26/4) = 0.99748427
tg(x/4) = tg(16.26/4) = 0.0710669

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Resolva a desigualdade cosx+raiz quadrada de 3.senx>raiz quadrada de dois, com 0<x<2pi

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