Aí DexteR, Se x e y são reais tais que \frac{x^2+y^2}{x^2-y^2}+\frac{x^2-y^2}{x^2+y^2}=k o valor de \frac{x^8+y^8}{x^8-y^8}+\frac{x^8-y^8}{x^8+y^8} é igual a:

(a)\frac{k^4+24k^2+16}{4k^3+16k}

(b)\frac{k^4-24k^2-16}{4k^3-16k}

(c)\frac{k^4+24k^2-16}{4k^3-16k}

(d)\frac{k^4+24k^2-16}{4k^3+16k}

(e)\frac{k^4-24k^2+16}{4k^3+16k}

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