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Danboa
@Danboa
November 2019
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Como desenvolver esta equação?
f(x) =
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Rich0031
F(x) = 1 + 1/3(√1 + cos 2x/2)² (cancela 2 com a raiz)
f(x) = 1 + 1/3.1 + cos 2x/2
f(x) = 1 + 1 + cos 2x/6
f(x) = 6 + 1 + cos 2x/6
f(x) = 7 + cos 2x/6
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f(x) = 1 + 1/3.1 + cos 2x/2
f(x) = 1 + 1 + cos 2x/6
f(x) = 6 + 1 + cos 2x/6
f(x) = 7 + cos 2x/6