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KAROLCOSTA
@KAROLCOSTA
April 2020
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Fatorando x² + 2y² + 3xy + x + y obtemos : OBS: TEM QUE DA
( x + y ) . (x + 2y + 1)
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x² + 2y² + 3xy + x + y(x + y)(x + 2y + 1) =
x^2 +2xy + x + xy +2y^2 + y
x^2 + 2y^2 +3xy + x + y
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Verified answer
x² + 2y² + 3xy + x + y(x + y)(x + 2y + 1) = x^2 +2xy + x + xy +2y^2 + yx^2 + 2y^2 +3xy + x + y