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SraAzevedo
@SraAzevedo
January 2020
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Inscrevendo-se nove meios aritméticos entre 15 e 45, qual é o sexto termo da PA?
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PauloBarros
A1 = 15
an = 45
9 meios aritméticos
[----------------------------------------------]
a1
a2 a3 a4 a5 a6 a7 a8 a9 a10
a11
a1 = 15
a11 = 45
n = 11
r = ?
an = a1 + (n - 1).r
a11 = a1 + (11 - 1).r
a11 = a1 + 10r
45 = 15 + 10r
45 - 15 = 10r
30 = 10r
10r = 30
r = 30/10
r = 3
(15,
18,21,24,27,30,33,36,39,42
,45)
an = a1 + (n - 1).r
a6 = a1 + (6 - 1).r
a6 = a1 + 5r
a6 = 15 + 5.3
a6 = 15 + 15
a6 = 30
R.: a6 = 30
******************************
a1 = 15
a2 =
a1 + r = 15 + 3
= 18
a3 =
a1 + 2r = 15 + 2.3 = 15 + 6
= 21
a4 =
a1 + 3r = 15 + 3.3 = 15 + 9
= 24
a5 =
a1 + 4r = 15 + 4.3 = 15 + 12 =
27
a6 =
a1 + 5r = 15 + 5.3 = 15 + 15
= 30
a7 =
a1 + 6r = 15 + 6.3 = 15 + 18
= 33
a8 =
a1 + 7r = 15 + 7.3 = 15 + 21
= 36
a9 =
a1 + 8r = 15 + 8.3 = 15 + 24
= 39
a10
= a1 + 9r = 15 + 9.3 = 15 + 27
= 42
a11 = 45
28 votes
Thanks 35
PauloBarros
Disponha Brisa! bjs
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an = 45
9 meios aritméticos
[----------------------------------------------]
a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11
a1 = 15
a11 = 45
n = 11
r = ?
an = a1 + (n - 1).r
a11 = a1 + (11 - 1).r
a11 = a1 + 10r
45 = 15 + 10r
45 - 15 = 10r
30 = 10r
10r = 30
r = 30/10
r = 3
(15,18,21,24,27,30,33,36,39,42,45)
an = a1 + (n - 1).r
a6 = a1 + (6 - 1).r
a6 = a1 + 5r
a6 = 15 + 5.3
a6 = 15 + 15
a6 = 30
R.: a6 = 30
******************************
a1 = 15
a2 = a1 + r = 15 + 3 = 18
a3 = a1 + 2r = 15 + 2.3 = 15 + 6 = 21
a4 = a1 + 3r = 15 + 3.3 = 15 + 9 = 24
a5 = a1 + 4r = 15 + 4.3 = 15 + 12 = 27
a6 = a1 + 5r = 15 + 5.3 = 15 + 15 = 30
a7 = a1 + 6r = 15 + 6.3 = 15 + 18 = 33
a8 = a1 + 7r = 15 + 7.3 = 15 + 21 = 36
a9 = a1 + 8r = 15 + 8.3 = 15 + 24 = 39
a10 = a1 + 9r = 15 + 9.3 = 15 + 27 = 42
a11 = 45