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AcrisiaSouza
@AcrisiaSouza
October 2019
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Insira 6 meios aritméticos entre 11 e 53
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TiagoEd
A1 = 11
a8 = 53
a8 = a1 + 7r
53 = 11 + 7r
7r = 53 - 11
7r = 42
r = 42/7
r = 6
Então, a P.A. será: (11, 17, 23, 29, 35, 41, 47, 53).
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Lista de comentários
a8 = 53
a8 = a1 + 7r
53 = 11 + 7r
7r = 53 - 11
7r = 42
r = 42/7
r = 6
Então, a P.A. será: (11, 17, 23, 29, 35, 41, 47, 53).