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AcrisiaSouza
@AcrisiaSouza
October 2019
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Quantos termos possui a PA (6, 9, 12, 15, ...231)?
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TiagoEd
A1 = 6
an = 231
r = a2 - a1 = 9 - 6 = 3
n = ?
an = a1 + (n-1) * r
231 = 6 + (n-1) * 3
231 = 6 + 3n - 3
3n = 231 - 6 + 3
3n = 234 - 6
3n = 228
n = 228/3
n = 76
1 votes
Thanks 1
nemmatonada
An = a1 + (n - 1) r
231 = 6 + (n - 1)3
231 = 6 + 3n - 3
231 - 6 + 3 = 3n
n = 228/3
n = 76
0 votes
Thanks 1
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Lista de comentários
an = 231
r = a2 - a1 = 9 - 6 = 3
n = ?
an = a1 + (n-1) * r
231 = 6 + (n-1) * 3
231 = 6 + 3n - 3
3n = 231 - 6 + 3
3n = 234 - 6
3n = 228
n = 228/3
n = 76
231 = 6 + (n - 1)3
231 = 6 + 3n - 3
231 - 6 + 3 = 3n
n = 228/3
n = 76