Resposta:
2^(x²)*2^(x)=2^(-3x)
2^[x²+x] =2^(-3x)
x²+x=-3x
x²+3x+x=0
x*(x+4)=0
x'=0
x''=-4
soma=0-4=-4
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Resposta:
2^(x²)*2^(x)=2^(-3x)
2^[x²+x] =2^(-3x)
x²+x=-3x
x²+3x+x=0
x*(x+4)=0
x'=0
x''=-4
soma=0-4=-4