Resolva o sistema:
B = C + 6
B - 2 = 3(A - 2)
B + 1 = A + 1 + C + 1
Quero a resolução por favor!
B = C + 6
B - 2 = 3(A - 2)
B + 1 = A + 1 + C + 1
Quero a resolução por favor!
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P1:
B-2= 3(A-2)
C+6-2=3(A-2)
C+4=3A-6
C=3A-10
P2:
B+1=A+1+C+1
C+6+1=A+1+3A-10+1
C+6=4A-8
4A=8+6+C
4A=14+C
A=(14+C)/4
P3:
B+1=A+1+C+1
B+1=A+1+C+1
B+1=(14+C)/4+1+C+1
B+1=(14+C)/4+(8+4C)/4
B+1=(14+8+C+4C)/4
B+1=(22+5C)/4
C+6+1= (22+5C)/4
C+7= (22+5C)/4
4(C+7)= 22+5C
4C+28=22+5C
4C-5C=22-28
-C=-6
C=6
Para B=C+6 temos:
B=6+6=12
B=12
Para A=(14+C)/4 temos:
A=14+6/4=20/4=
A=5