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DanielAntunes27
@DanielAntunes27
May 2020
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Resolver essa equação do segundo grau
x²-4x-140=0
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dorival5
Delta=b²-4.a.c
Delta= (-4)²-4.1.-140
Delta= 576
-b+-raiz de Delta/2a= -(-4)+raiz de 576/2a= 14
-b-raiz de delta/2a= -(-4)-raiz de 576/2a= -10
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Comentários
x²-4x-140=0
Δ = b2 -4ac
Δ.
= (-4)² - 4 * 1 * (-140)
Δ.
= 16 + 560
Δ
.
= 576
Báskara X = 4+ou- raiz quadrada de delta 576 / 2*1
X = 4 +ou- 24 / 2
X'= 4 + 24 / 2 = 28 / 2 = 14 X"= 4-24/2 = -20/2 = -10
Solução {14, -10}
1 votes
Thanks 0
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Lista de comentários
Delta= (-4)²-4.1.-140
Delta= 576
-b+-raiz de Delta/2a= -(-4)+raiz de 576/2a= 14
-b-raiz de delta/2a= -(-4)-raiz de 576/2a= -10
Δ = b2 -4ac
Δ. = (-4)² - 4 * 1 * (-140)
Δ. = 16 + 560
Δ. = 576
Báskara X = 4+ou- raiz quadrada de delta 576 / 2*1
X = 4 +ou- 24 / 2
X'= 4 + 24 / 2 = 28 / 2 = 14 X"= 4-24/2 = -20/2 = -10
Solução {14, -10}