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AlineB
@AlineB
April 2020
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Sabendo que log 2 = a e log 3 = b, calcule em função de a e b:
a) log 5
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mozarthrocha
Log 5 = log (60/12) = log (3x2x10)/log (3x2x2) = (log 3+log2+log10) / (log 3 + log 2+ log 2) = (b+a+1) / (b+a+a) = (a+b+1) / 2a+b
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AlineB
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