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LuaHell
@LuaHell
December 2019
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Calcule o valor da expressão x+y-z, sabendo que x=log0,001^6, y=㏒243 na base 3 e z=㏒√27 na base 3.
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DanieldsSantos
Olá!
Vamos determinar:
x=log0,001^6
x=log(10^-3)^6
x=log10^-18
x=-18
------
y=㏒3 243
y=log3 3^5
y=5
-------
z=㏒3 √27
z=(log3 27)/2
z=3/2
Então:
x+y-z
=> -18+5-3/2
=> -13-3/2
=> (-26-3)/2
=> -29/2
Espero ter ajudado!
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Vamos determinar:
x=log0,001^6
x=log(10^-3)^6
x=log10^-18
x=-18
------
y=㏒3 243
y=log3 3^5
y=5
-------
z=㏒3 √27
z=(log3 27)/2
z=3/2
Então:
x+y-z
=> -18+5-3/2
=> -13-3/2
=> (-26-3)/2
=> -29/2
Espero ter ajudado!