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KatherynKopchinski
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January 2020
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Considere a função no conjunto dos reais, definida por f(x) =
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glautonribeiro
F(x) = 2 ^x + 2^-x , [f(-2) +f(2)]f(0)
f(0) = 2^0 + 2^-0 [17/4 + 17/4]2
f(0) = 1 +1 = 2 [17+17/4]2
34/4*2 = 34/2
= 17
f(2) = 2^2 + 2^-2
f(2)= 4 + 1/4 = 17/4
f(-2)= 2^-2 + 2^2
f(-2)= 1/4 + 4 17/4
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f(0) = 2^0 + 2^-0 [17/4 + 17/4]2
f(0) = 1 +1 = 2 [17+17/4]2
34/4*2 = 34/2 = 17
f(2) = 2^2 + 2^-2
f(2)= 4 + 1/4 = 17/4
f(-2)= 2^-2 + 2^2
f(-2)= 1/4 + 4 17/4