Qual a solução da equaçao log2 ( x + 1 ) + log2 (x-2) = 2 ?.... Pergunta de ideia deKatherynKopchinski

KatherynKopchinski @KatherynKopchinski

January 2020 1 84 Report

Qual a solução da equaçao log2 ( x + 1 ) + log2 (x-2) = 2 ?

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ProfRafael $log_{2}(x+1) + log_{2}(x-2)=2 \\ \\ log_{2}(x+1)(x-2)=2 \\ \\ 2^{2}=(x+1)(x-2) \\ \\ x^{2}-2x+x-2 = 4 \\ \\ x^{2}-x-2-4=0 \\ \\ x^{2}-x-6=0 \\ \\ D=(-1)^{2}-4(1)(-6) \\ D=1+24=25 \\ \sqrt{D} = \sqrt{25} =5 \\ \\ x'=(1+5)/2 = 6/2=3 \\ \\ x''=(1-5)/2=-4/2=-2 (nao) \\ \\$

Resposta: x = 3

Espero ter ajudado.

3 votes Thanks 1

KatherynKopchinski SS, ajudou, obg :)

ProfRafael Obrigado!

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