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Welveson001
@Welveson001
December 2019
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Resolva a equaçao modular, |3x-4| =x^2.
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emaoliver97
|3x-4|=x^2
Temos dois casos, quando (3x-4)=x^2 ou -(3x-4)=x^2, pela definição do modulo
1ºCaso
(3x-4)=x^2
x^2-3x+4=0
Δ
=b²-4ac
Δ=(-3)²-4*1*4
Δ=-7
Não tem solução
Caso 2
-(3x-4)=x^2 ==> x^2+3x-4=0
Δ=b²-4ac
Δ=(3)²-4(1)(-4)
Δ=25
√Δ=5
x'=(-3+5/2) => x'=1
x''=(-3-5/2) => x''=-4
Ou seja a solução é {1.-4}
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Lista de comentários
Temos dois casos, quando (3x-4)=x^2 ou -(3x-4)=x^2, pela definição do modulo
1ºCaso
(3x-4)=x^2
x^2-3x+4=0
Δ=b²-4ac
Δ=(-3)²-4*1*4
Δ=-7
Não tem solução
Caso 2
-(3x-4)=x^2 ==> x^2+3x-4=0
Δ=b²-4ac
Δ=(3)²-4(1)(-4)
Δ=25
√Δ=5
x'=(-3+5/2) => x'=1
x''=(-3-5/2) => x''=-4
Ou seja a solução é {1.-4}