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Fergerrard
@Fergerrard
December 2019
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Calcule a razão da PA (x+3, 2x-1, x+5)
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Eduardaluizanp
PA (x+3, 2x-1, x+5)
primeiro para saber a razão precisa saber o valor de x
(x+5)- (2x-1)= (2x-1)- (x+3)
x+5-2x+1=2x-1-x-3
x-2x-2x+x=-1-3-5-1
-2x=-10 (.-1)
2x=10
x= 10/2
x=5
agora sim a razão
(x+5) (2x-1)
5+5=10 2.5-1
10-1
9
razão
10-9=1
2 votes
Thanks 1
albertrieben
ele pede a razão
fergerrard
isso
fergerrard
caiu na prova, fiz diferente, mas deu o mesmo resultado. Muito obrigada
albertrieben
Bom dia
PA
a1 = x + 3
a2 = 2x - 1
a3 = x + 5
a2 = (a1 + a3)/2
2x - 1 = (x + 3 + x + 5)/2
4x - 2 = 2x + 8
4x - 2x = 8 + 2
2x = 10
x = 5
a1 = x+ 3 = 8
a2 = 2x - 1 = 9
a3 = x + 5 = 10
razão
r = a2 - a1 = 9 - 8 = 1
1 votes
Thanks 1
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Lista de comentários
primeiro para saber a razão precisa saber o valor de x
(x+5)- (2x-1)= (2x-1)- (x+3)
x+5-2x+1=2x-1-x-3
x-2x-2x+x=-1-3-5-1
-2x=-10 (.-1)
2x=10
x= 10/2
x=5
agora sim a razão
(x+5) (2x-1)
5+5=10 2.5-1
10-1
9
razão
10-9=1
PA
a1 = x + 3
a2 = 2x - 1
a3 = x + 5
a2 = (a1 + a3)/2
2x - 1 = (x + 3 + x + 5)/2
4x - 2 = 2x + 8
4x - 2x = 8 + 2
2x = 10
x = 5
a1 = x+ 3 = 8
a2 = 2x - 1 = 9
a3 = x + 5 = 10
razão
r = a2 - a1 = 9 - 8 = 1