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Dani76561
@Dani76561
December 2019
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Considere a sequencia de numeros a1=0,2; a2=0,02;... an=0,000...02. O valor da expressão a1+a2+a3+...+an+... é?
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MrChem
Observe a sequência:
a1+a2 = 0,2+0,02 = 0,22
a1+a2+a3 = 0,2+0,02+0,002 = 0,222
a1+a2+a3+a4 = 0,2+0,02+0,002+0,0002 = 0,2222
Assim, a soma destes n termos será 0,222222... (dízima periódica)
1 votes
Thanks 1
Dani76561
Muito obrigada!!!!! Está certinho.
MrChem
Por nada!
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Lista de comentários
a1+a2 = 0,2+0,02 = 0,22
a1+a2+a3 = 0,2+0,02+0,002 = 0,222
a1+a2+a3+a4 = 0,2+0,02+0,002+0,0002 = 0,2222
Assim, a soma destes n termos será 0,222222... (dízima periódica)