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Dani76561
@Dani76561
December 2019
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Sejam r1 e r2 as raízes da equação de 2º grau 2x² - 6x + 3 = 0. Determine o valor de: r1² + r2²
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X'+x''=-b/a=3
x'*x''=c/a=3/2
(x'+x'')²=9
x'²+x''²+2*x'*x''=9
x'²+x''²=9 -2*3/2=6
12 votes
Thanks 7
Dani76561
a Resposta correta seria -3
Dani76561
Desculpa. Eu que copiei o enuciado errado
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x'*x''=c/a=3/2
(x'+x'')²=9
x'²+x''²+2*x'*x''=9
x'²+x''²=9 -2*3/2=6